Question 873724
Perpendicular line slopes are negative reciprocals.
{{{(-5)*m[perp]=-1}}}
{{{m[perp]=1/5}}}
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{{{y=(1/5)x+b}}}
Use the point to solve for {{{b}}}.
{{{3=(1/5)(0)+b}}}
{{{b=3}}}
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{{{y=(1/5)x+3}}}
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{{{drawing(300,300,-5,5,-5,5,grid(1),circle(0,3,0.3),graph(300,300,-5,5,-5,5,-5x-4,(1/5)x+3))}}}