Question 873648
y=x^2+4x+7
y = (x+2)^2 -4  +7
y = (x+2)^2 + 3,  V(-2,3)
0 = (x+2)^2 + 3
x = -2 ± i√3  NO x-intercepts
{{{drawing(300,300,   -20,20,-20,20, grid(1), blue(line(-2,20,-2,-20)),  
circle(-2, 3,0.5),
graph( 300, 300, -20,20,-20,20, 0, x^2+4x+7 ) )}}}