Question 873647
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Hi
{{{a[n] = 2 + (n-1)3}}}
       3n-1 >100
         3n > 101
          n > 101/3 = 33 2/3, {{{  highlight_green(n>34) }}} 
checking...
{{{a[33] = 2 + (n-1)3 = 98}}}
{{{a[34] = 2 + (n-1)3 = 101}}}