Question 873559
The amount of money you earn (in pennies) on the n-th day will be 2^(n-1).
The job that pays $1000 earns you 100000 pennies.
Is there a day (n<30) in which you start to earn more than 100000 pennies?
2^(n-1) = 100000 = 10^5
log10(2^(n-1)) = log10(10^5)
(n-1)log10(2) = 5
n = 5/log10(2) + 1
This gives n = 17.6.  So on the 18th day, you will already start earning more than the $1000, not even counting all the money you've earned up to that point.
Take the penny-doubling job...