Question 873239
{{{y = -2x^2 + 5x}}}
{{{y= 4x - 1}}}
So,
{{{-2x^2 + 5x=4x - 1}}}
{{{2x^2-x-1=0}}}
{{{(x-1)(2x+1)=0}}}
Two solutions:
{{{x-1=0}}}
{{{x=1}}}
Then,
{{{y=4(1)-1=3}}}
and
{{{2x+1=0}}}
{{{2x=-1}}}
{{{x=-1/2}}}
Then,
{{{y=4(-1/2)-1=-2-1=-3}}}
(1,3) and (-1/2,-3)
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graph(300,300,-5,5,-5,5,-2x^2+5x,4x-1))}}}