Question 73620
Let D = the number of dimes ($0.10) and Q = the number of quarters ($0.25).
Jose has 6 more dimes than quarters.  This can be written:
D = Q+6
The total amount of money is $1.65.  This can be written:
($0.10)D+($0.25)Q = $1.65 Now substitute the first equation for D here.
($0.10)(Q+6)+($0.25)Q = $1.65 Simplify and solve for Q.
($0.10)Q + $0.60 + ($0.25)Q = $1.65 Combine like-terms.
($0.35)Q + $0.60 = $1.65 Subtract $0.60 from both sides.
($0.35)Q = $1.05 Divide both sides by ($0.35)
Q = 3 This is the number of quarters Jose has.
D = Q+6
D = 3+6 = 9  This is the number of dimes Jose has.