Question 872804
The denominator of the second rational expression is (x-2)(x+3).  The first step next is just as you would do for ordinary base ten numbers; bring all expressions to higher terms to use the lowest common denominator.  Same denominator as the second expression.


{{{((2x)(x-2)-(5x)+(3x)(x-2))/((x-2)(x+3))}}}


{{{(2x^2-4x-5x+3x^2-6x)/((x-2)(x+3))}}}
{{{highlight((5x^2-15x)/((x-2)(x+3)))}}}
{{{5x(x-3)/((x-2)(x+3))}}}
Probably want the answer as {{{highlight((5x^2-15x)/(x^2+x-6))}}}