<PRE><B>Question 872809</B>
Let the width  be x															
..															
Length   of	picture		17	in											
width of  	picture		11	in											
															
Area =			187		In^2										
Area of 	picture +frame		315	In^2											
length of 	picture +frame				17	+	2	x 					
width of	picture	 +frame	11	+	2	x								
															
(	17	+	2	x	)	(	11	+	2	x	)		=	315
															
	187	+	34	x	+	22	x	+	4	X^2			=	315
	4	X^2		+	56	x		-128	=	0					



4x^2+64x-8x-128=0

4x(x+16)-8(x+16)=0

(x+16)(4x-8)=0

x=-16 OR x=2

taking positive value

the outside dimensions are 
19 by 13 in

</PRE>