Question 872799
Q:Find the equation of the quadratic function with vertex (6,-2) and zeros of 2 and 10
A:
The quadratic function is y = a(x - 2)(x - 10) where a ≠ 0.
The point (6, -2) is on the graph of the parabola so
-2 = a(6 - 2)(6 - 10)
-16a = -2
a = 1/8
Therefore, the quadratic function is {{{highlight(y = f(x) = (1/8)(x - 2)(x - 10))}}} or {{{highlight(y = f(x) = 0.125x^2 - 1.5x + 2.5))}}}