<PRE><B>Question 872753</B>
Recent information published by the U.S. Environmental Protection Agency indicates that Honda is the manufacturer of four of the top nine vehicles in terms of fuel economy.
P(honda) = 4/9
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a. Determine the probability distribution for the number of Hondas in a sample of three cars chosen from the top nine. 
Binomial Problem with n = 3 and p(H) = 4/9
mean = np = 3(4/9( = 4/3
std = sqrt(npq) = sqrt((4/3)(5/9)) = sqrt(20/27) = (2/3)sqrt(5/3)
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b. What is the likelihood that in the sample of three at least one Honda is included?
P(at least 1) = 1 - P(none)
P(at least 1) = 1 - (5/9)^3 = 0.8285
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Cheers,
Stan H. 
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