<PRE><B>Question 872689</B>
Let P(A) =Type 1 is defective=0.09
P(B)=Type 2 is defective=0.05
P(A and B)=Both are defective=0.02
P(A or B)=P(A)+P(B)-P(A and B)
P(Type 1 is defective or type 2 is defective) indicates 
P(A or B)=0.09+0.05-0.02=0.12

Probability that none are defective=1-0.12=0.88

Ans=0.88

------------------Peace out hun--------------- :)
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