Question 872641
Never heard of a train speed of 1290 km/h. Love to go. If your problem says 1290 then add a zero and recalculate

speed difference =129-x

distance to cross 300m = 0.3 km

d/r = t

.3/129-x= 2/60

60*.3=2(129-x)

18 =258-2x

2x= 240

x=120 km/h