<PRE><B>Question 872637</B>
age of brother is twice than the age of sister,three years back age of brother was as three time as the age of the sister find the present ages and also show me
that how to solve it
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let x=present age of sister
2x=present age of brother
..
3 yrs ago:
x-3=age of sister
2x-3=age of brother
age of brother was three times the age of the sister
2x-3=3(x-3)
2x-3=3x-9
x=6
2x=12
present age of sister=6
present age of brother=12
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