Question 872613
"Kate invests $48000, part at 9% and the rest at 7%. The annual return on the investments is actually the same. How much did she invest at each rate?" 
.
Let x = amount invested at 9%
then
48000-x = amount invested at 7%
.
.09x = .07(48000-x)
.09x = 3360-.07x
.16x = 3360
x = 3360/.16
x = $21000 (amount invested at 9%)
.
amount invested at 7%:
48000-21000= $27000