Question 872216
 Hannah is walking along a road that goes North.
 She turns 45 degrees to the right and walks 100 feet.
 She then turns right 140 degrees to head back to the road.
 How far is it to the road?
:
Draw this out, it will form a triangle, find the interior angles of the triangle
When she turns 45 degrees, the interior angle 180 - 45 = 135 degrees = A
When she turns 140 degrees, the interior angele 180 - 140 = 40 degrees = B
Angle C: 180 - 40 - 135 = 5 degrees is angle C
Side c opposite angle C = 100 feet
Use the law of sines {{{a/sin(A)}}} = {{{b/sin(B)}}} = {{{c/sin(C)}}}
Find side a, which is opposite angle A,is the distance to the road
{{{a/sin(135)}}} = {{{100/sin(5)}}}
{{{a/.707}}} = {{{100/.087}}}
.087a = 100*.707
a = {{{70.7/.087}}}
a = 812.6 ft from her last turn to the road going north
:
How far did she walk along the northbound road? 
Find side b, which is opposite angle B, is the northbound road
{{{b/sin(40)}}} = {{{100/sin(5)}}}
{{{b/.643}}} = {{{100/.087}}}
.087b = 100 * .643
b = {{{64.3/.087}}}
b = 738.8 ft the north bound side of the triangle