Question 872380
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Hi
 population: mean= 212, standard deviation = 6.1
Sample of 75
P(xbar > 213),   z = (213-212)/6.1/sqrt(75) = 1/.704 = 1.42
P(z > 1.42) = normalcdf(1.42,10)= .0778  0r 7.78%
TI syntax for P-value is normalcdf(smaller z, larger z) (Above: 10 a place-holder)