Question 872299
log(x-2) + log(x+1) = 1


=> log((x-2)(x+1))=log 10

=> (x-2)(x+1)=10

=> x^2-x-2=10

=> x^2-x-12=0

=>x^2-4x+3x-12=0

=>x(x-4)+3(x-4)=0

=> (x-4)(x+3)=0

x= 4 OR -3