Question 872354
I'm asking this for a third time :(
The equation of a circle is (x−4)^2+ (y+2)^2=16.
B) Find the radius of the circle with the given equation.
Can someone give me explanations on how they got the answer instead of just giving me the answer please?
The radius is 4, but I need to know how and the steps it takes to get to 4.
Thank you so much.
Answer 
equation of  circle given  (x-a)^2 +(y-b)^2 =r^2 where a,b are coordinate of center of circle 
now given circle  is  (x−4)^2+ (y+2)^2=16    by comparison of  equations 
we can say the coordinate of centers is (4,2) and r^2 =16 
r=plus and minus 4 but radius of circle can not be  negative therefor r=4 radius of circle will be  4 only 
you should also know general equation of circle  is x^2 +y^2 =r^2 where center at origin (0,0)
  and radius is square root of r