Question 872300
Solve
a) log(base 2)(2m + 4) - log(base 2) (m-1) = 3
{{{log(2,(2m+4))-log(2,(m-1))=3}}}
{{{log(2,((2m+4)/(m-1)))=3}}}
(2m+4)/(m-1)=2^3=8
2m+4=8m-8
6m=12
m=2