Question 73491
Simplify:
{{{((2x^(-6)y^(-4)z^0)/(3^(-2)x^(-2)y^(-8)z^5))^3}}} First, make all of the negative exponents positive by moving them down or up, as appropriate.
{{{((2*3^2x^2y^8z^0)/(x^6y^4z^5))^3}}} Replace the {{{z^0}}} with 1 and cancel factors in the numerator and denominator where appropriate.
{{{((18y^4)/(x^4z^5))^3)}}} Now we'll cube every thing.
{{{5832(y^12/(x^12z^15))}}}