Question 872294
Two rules to know:


{{{a*log(b,x)=log(b,x^a)}}} and {{{log(b,x)+log(b,y)=log(b,xy)}}}.


After you use those rules properly, you could change the equation to exponential form, if that makes solving easier.  The actual steps are not shown here so that you have the opportunity to solve your given equation on your own.