Question 872175
{{{(10/(2y+8))-((7y+8)/(y^2-16))=-(8/(2y-8))}}}


{{{(10/(2(y+4)))-((7y+8)/((y+4)(y-4)))=-(8/(2(y-4)))}}}

LCM = 2(y+4)(y-4)

{{{(10*(y-4))-2(7y+8)=-8(y+4)}}}


10y-40-14y-16=-8y-32

simplify

4y=24
/4
y=6