Question 871911
I assume you mean 
{{{10x ^5+39 x^4+16x^3-82x^2-72x+8=0}}}
You can factor to,
{{{(x+2)^2(10x-1)(x^2-2)=0}}}
Four solutions
{{{x+2=0}}}
{{{x=-2}}}
and
{{{10x-1=0}}}
{{{10x=1}}}
{{{x=1/10}}}
and
{{{x^2-2=0}}}
{{{x^2=2}}}
{{{x=0 +- sqrt(2)}}}
.
.
.
{{{graph(300,300,-3,3,-30,30,(x+2)^2(10x-1)(x^2-2))}}}