Question 872074
p = .40,  n = 250
P(x = 95) = binompdf(250, .40, 95) = .0421  0r 4.21%
P(105 ≤ x ≤ 110) = binomcdf(250, .40, 110)- binomcdf(250, .40, 104) = .9119 - .7203 = .1916  0r 19.16%
P(x  ≤ ≤  85) = binomcdf(250, .40, 85) = .0297  0r 2.97%
P(x ≥ 95) = 1 - (1-binomcdf(250, .40, 94) = .7605  0r 76.05%