Question 872059
___1_2_3__4__5__6
1|_2_3_4__5__6__7
2|_3_4_5__6__7__8
3|_4_5_6__7__8__9
4|_5_6_7__8__9_10
5|_6_7_8__9_10_11
6|_7_8_9_10_11_12
P(7) = 6/36 = 1/6 = .1667,  n = 15
P(x =3) = binompdf(15, .1667, 3) = .2363  0r 23.63%