Question 872023
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Hi
mean of 14 days and a standard deviation of 3 days.
Normal Distribution
P(x &#8804; 10), z =(10-14)/3 =  -4/3, P(z &#8804; -1.3333) = 9.12%
P(x &#8805; 21), z =(21-14)/3 =  7/3,
 P(x &#8805; 21) = 1 - P(x <21) = 1 - P(z < 2.3333) = .0098 0r.98%