Question 871559
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Hi
p(white) = 1/6,   n = 4
P(x = 3) = 4C3(1/6)^3(5/6)^1  0r binompdf(4, 1/6, 3) = 0.0154
P(x &#8805; 2) = 1 - binomcdf(4, .1667, 1) = 0.132