Question 871467
{{{A=5+2B}}}
{{{A*B=18}}}
Substituting,
{{{(5+2B)B=18}}}
{{{2B^2+5B-18=0}}}
{{{(B-2)(2B+9)=0}}}
Two solutions:
{{{B-2=0}}}
{{{B=2}}}
Then,
{{{A=18/2=9}}}
and
{{{2B+9=0}}}
{{{2B=-9}}}
{{{B=-9/2}}}
Then,
{{{A=18/(-9/2)=-4}}}