Question 871486
(1/secx+tanx)=(1-sinx/cosx)


{{{(1*(secx-tanx))/((secx+tanx)(secx -tanx))}}}


{{{(1*(secx-tanx))/(sec^2(x) -tan^2(x))}}}


(sec^2(x) -tan^2(x))=1

we get
(secx - tanx)

{{{(1/cosx)-(sinx/cosx)}}}


{{{(1-sinx)/cosx}}}