Question 73390
Given:
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7(3x+11) = 9(3-6x)
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Solve for x
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First, on the left side multiply the 7 by each of the terms in the parentheses to get:
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21x + 77 = 9(3 - 6x)
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Now on the right side multiply 9 times each of the terms in the parentheses to get:
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21x + 77 = 27 - 54x
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Now the object is to get all the terms with x on the right side and all the terms that
are just numbers onto the right side.
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Begin by adding 54x to both sides of the equation.  On the right side this cancels
the - 54x.  The equation then becomes:
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75x + 77 = 27
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Now subtract 77 from both sides to get rid of the + 77 on the left side.  When you do
this subtraction the equation becomes
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75x = -50
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Finally solve for x by dividing both sides by the multiplier of x which is 75.
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x = -50/75 = -2/3
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So the answer to this problem is x = -2/3
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Hope that this gives you a little insight into the procedures that can be used to solve
equations.