Question 871228
The parabola is in vertex form.
The vertex is (-2,-4) and since the multiplier is {{{-4}}} in front of {{{(x+2)^2}}}, the parabola opens downwards and the max value is {{{y=-4}}}.
Here's a graph,
{{{drawing(300,300,-8,8,-14,2,grid(1),blue(line(-2,-20,-2,20)),graph(300,300,-8,8,-14,2,-4(x+2)^2-4))}}}
Looks like the function increases from {{{x=-infinity}}} to {{{x=2}}},
decreases from {{{x=-2}}} to {{{x=infinity}}}, and is always negative.