Question 871117
x(x-2) = 3
x^2 - 2x - 3 = 0
(x-3)(x+1) = 0,    x = 3
Root x = -1 is an extraneous root
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]  Applied
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1] Applied