Question 73415
If you're solving for x, then
{{{0=-x^2+2x+3}}}Let y=0 and factor out a -1
{{{0=-(x^2-2x-3)}}}Factors to
{{{0=-(x+1)(x-3)}}}Here's the product of factors
{{{x+1=0}}}Set each factor equal to zero
{{{x=-1}}}Here's one answer
{{{x-3=0}}}
{{{x=3}}}Here's another answer
{{{graph( 300, 200, -6, 5, -10, 10, -x^2+2x+3)}}}
Hope that helps