Question 871077
{{{X^(-2)-x^(-1)=6}}}


{{{(1/x^2)-(1/x) =6}}}


multiply by x^2

{{{1-x=6x^2}}}
{{{6x^2+x-1=0}}}

{{{(6x^2+3x-2x-1)=0}}}

{{{6x(x+(1/2))-2(x+(1/2))=0}}}

(x+(1/2))(6x-2)=0

any  of the factors may be zero 

So x= -1/2

OR x=1/3