Question 870918
Write an equation in standard form for the hyperbola with center (0,0) , vertex (0,6) , and focus (0,8). 
***
Given hyperbola has a vertical transverse axis with center at (0,0)
Its standard form of equation: {{{y^2/a^2-x^2/b^2=1}}}
a=6
a^2=36
c=8
c^2=64
c^2=a^2+b^2
b^2=c^2-a^2=64-36=28
equation: {{{y^2/36-x^2/28=1}}}