Question 870988
{{{2x+10=2(x+5)}}}
{{{x^2-32x-10}}} does not divide evenly by {{{2}}} or by {{{x+5}}}. In fact, it cannot be factored into anything with rational coefficients.
The polynomials {{{x^2-32x-10}}} and {{{2x+10}}} have no factor in common.
Finding a common multiple of {{{x^2-32x-10}}} and {{{2x+10}}}
is like finding a common multiple of {{{6}}} and {{{35}}} .
Since they do not have any common factors, all you can do is multiply them together, and you get the least common multiple that way.
Depending on what you are asked for, or what you are going to do with that common multiple,
you may want to leave the product as {{{(x^2-32x-10)(2x+10)}}} ,
or maybe you would want to actually do the multiplication.
{{{(x^2-32x-10)(2x+10)=(x^2-32x-10)2x+(x^2-32x-10)10=2x^3-64x^2-20x+10x^2-320x-100=2x^3-54x^2-340x-100}}}