Question 870819
y^2=-4y+2x+1 
y^2+4y= 2x+1 
(y+2)^2 = 2x + 1 + 4
(y+2)^2 = 2x + 5
0r
 x = (1/2)(y+2)^2 -5/2   4p = 2, p = .5
Parabola Opening right V(-2.5, -2) line of symmetry:  y = -2
focus (-2, -2) directrix = x = -3