Question 870733

The sum of 5 times an integer and 2 times it's square is 133. What is the integer?
You have to develop an equation and then after that use the quadratic formula to solve for the unknowns. 
I ended up with 2xsquared +5-133=0. When I put this in the quadratic formula I ended up with 7.275. 
I beleive that I'm wiring so would you kindly do it for me from beginning to end so I can see where I made my mistake. Thank you.
<pre>
Let integer be N
Then, {{{5N + 2N^2 = 133}}}
{{{2N^2 + 5N - 133 = 0}}}
(N - 7)(2N + 19) = 0 ------- Factoring {{{2N^2 + 5N - 133}}}
N - 7 = 0                OR          2N + 19 = 0
N, or integer = {{{highlight_green(7)}}}      OR          2N = - 19 (ignore as this will NOT result in an integer value.
You can do the check!! 

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