<PRE><B>Question 870685</B>
Two trains start from towns 192 miles apart and travel toward each other on parallel tracks. They pass each other 1.6 hour later. if one train travels 10 mph faster then the other find the speed of each train
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Slower train DATA:
distance = x miles ; rate = r mph ; time = x/r hrs
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Faster train DATA:
distance = 192-x miles ; rate = r+10 mph ; time = (192-x)/(r+10) hrs
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Equations:
x/r = 1.6 hrs
x = 1.6r
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(192-x)/(r+10) = 1.6
(192-1.6r)/(r+10) = 1.6
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192 - 1.6r = 1.6r+ 16
3.2r = 176
r = 55 mph (slower train rate)
r+10 = 65 mph (faster train rate)
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Cheers,
Stan H.
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