Question 870659
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Hi
p = .40,  n = 250
P(x = 95) = 250C95(.40)^95(.60)^155 =  binompdf(250,.40,95) = .0421  0r 4.21%
P(x &#8804; 85) = binomcdf(250,.40,55) = .0297  0r 2.97%
P(x &#8805; 95) = 1 - binomcdf(250,.40,94)= .7605