Question 870646
{{{sqrt(2x+7) = 5}}} Start with the given equation.



{{{(sqrt(2x+7))^2 = 5^2}}} Square both sides



{{{2x+7 = 25}}} Now that the square root is gone, we solve for x like normal



{{{2x = 25-7}}}



{{{2x = 18}}}



{{{x = 18/2}}}



{{{x = 9}}}



The *possible* answer is {{{x = 9}}}, but we have to check it



Check: Plug in x = 9 and simplify



{{{sqrt(2x+7) = 5}}}



{{{sqrt(2*9+7) = 5}}}



{{{sqrt(18+7) = 5}}}



{{{sqrt(25) = 5}}}



{{{5 = 5}}} Works


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The only solution is {{{x = 9}}}