Question 870642
log(x)+log(x+3)=log(10)



log(x*(x+3))=log(10)



10^[log(x*(x+3))]=10^[log(10)]



x*(x+3) = 10



x^2+3x = 10



x^2+3x-10 = 0



(x + 5)(x - 2) = 0



x + 5 = 0 or x - 2 = 0



x = -5 or x = 2



The domain of log(x) is x > 0, so we toss x = -5. 



The only solution is x = 2.