Question 865694
x = 5,   y = -2

Your matrix

	X1	X2	b
	3	1	13
	2	-7	24


	X1	X2
	3	1
	2	-7
Determinant is not zero, therefore inverse matrix exists



	X1	X2
	7/23	1/23
	2/23	-3/23

Multiply the inverse matrix by the solution vector

	X
	5
	-2


Solution set:

x1 = 5  x2=-2