Question 870467
15 towels: 6W, 5B, 4BL
1. 15C3 = {{{15*14*13/(3*2)}}} = 455
2. {{{(6C1)(5C1)(4C1) = 6*5*4}}} = 120
3.  120/455 = 24/91
4.  15C5 = 3003
5.  {{{((4C3)(5C2))/3003}}}