Question 73268
{{{4x^2-32x+60}}}
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Notice that all the coefficients have 4 as a common factor.  So you can pull the 4 out to get:
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{{{4*(x^2 - 8x + 15)}}}
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Notice that the factor pairs of 15 are (1*15) and (5*3). Can either of these factor pairs
be used to get -8 as their sum and +15 as their product?  How about -5 and -3?
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This results in:
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{{{4*(x-5)*(x-3)}}}
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You can multiply these three factors out and see if you don't get back to the original
expression.
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Hope this helps.  Remember that if the {{{x^2}}} term has a coefficient to see if that 
coefficient is a common factor of all the other terms.  If it is, factor it out of all
the terms.  Factoring is a lot easier if the leading term (in this case {{{x^2}}} has
a coefficient (multiplier) of just 1.