Question 870165
{{{log(2,(x+3)) + log(2,x) = 2}}}
Adding logs --> multiplication
{{{log(2,x*(x+3)) = 2}}}
{{{log(2,(x^2+3x)) = 2}}}
Then, 
{{{log(2,(x^2+3x)) = log(2,4)}}}
{{{x^2+3x = 4}}}
Now it's a quadratic.
Check both zeroes, don't accept the log of a negative number.