<PRE><B>Question 870014</B>
The probability that the committee of 3 would consist of all 3 men is equal to:


30/50 * 29/49 * 28/48 = .2071


The probability that at least one of the committee members would be female is equal to:


1 - .2071 = .7929


round these answers to 2 decimal places and you get:


p(all males) = .21
p(at least 1 female) = .79


</PRE>