Question 870085
{{{sqrt (x-4) + 4=x}}}
{{{sqrt(x-4)=x-4}}}
{{{x-4=(x-4)^2}}}
{{{x-4=x^2-8x+16}}}
{{{x^2-9x+20=0}}}
{{{(x-4)(x-5)=0}}}
Two solutions:
{{{x-4=0}}}
{{{x=4}}}
and
{{{x-5=0}}}
{{{x=5}}}