Question 870048
<pre><font face = "consolas" color = "indigo" size = 3><b>
Hi
log3(3x+2)-log3(x)=2
(3x+2)/x = 9
 3x+2 = 9x
    2 = 6x
  1/3  = x
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x] Applied
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]  Applied
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]