Question 869911
You need to factor the {{{x^2-4}}} denominator, and get a common denominator for both fractions.
{{{x/(x^2-4)}}} - {{{1/(x+2)}}}={{{x/((x+2)(x-2))-1/(x+2)}}}={{{x/((x+2)(x-2))-(x-2)/((x+2)(x-2))=(x-(x-2))/((x+2)(x-2))=(x-x+2)/((x+2)(x-2))}}}={{{2/(x^2-4)}}}